titik balik maksimum ( titik puncak) dari fungsi kuadrat 9-6x-3x kuadrat?

-3x^2-6x+9
a=-3
b=-6
c=9

Xp=-b/2a=6/-6=-1
Yp=-(b^2-4ac)/4a=-144/-12=12

titik (-1,12)

Kelas 10 Matematika
Bab Persamaan dan Fungsi

f(x) = 9 - 6x - 3x²
a = -1; b = -6; c = 9.

sumbu simetri
= -b/2a
= - (-6)/(2 . (-3))
= -1

f(-3) = 9 - 6 . (-1) - 3 . (-1)²
f(-3) = 9 + 6 - 3 . 1
f(-3) = 15 - 3
f(-3) = 12

Titik balik maksimum (-1, 12)