tentukan dy/dx dari x^2 +2x +3y^2= 2

jawab

x²  + 2x + 3y² = 2
dy/dx = 

2x + 2 + 6y (dy/.dx) = 0
6y (dy/dx) = -2 x - 2
dy/dx = (-2x - 2)/6y
dy/dx = -2(x+1)/ 6(y)
dy/dx = -(x +1)/ (3y)
dy/dx = (-x - 1)/ (3y)