tentukan hp dari A.3\x+2 = 1\4 + 1 \ 3x+6 B. [ 2x + 5 ] - 3 > 7
Matematika
adhanur12
Pertanyaan
tentukan hp dari
A.3\x+2 = 1\4 + 1 \ 3x+6
B. [ 2x + 5 ] - 3 > 7
A.3\x+2 = 1\4 + 1 \ 3x+6
B. [ 2x + 5 ] - 3 > 7
1 Jawaban
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1. Jawaban marisaalifa22
[tex]a. \\ \frac{3}{x + 2} = \frac{1}{4} + \frac{1}{3x + 6} \\ \frac{3}{x + 2} = \frac{3x + 6 + 4}{12x + 24} \\ 3(12x + 24) = x + 2(3x + 10) \\ 36x + 72 = {3x}^{2} + 10x + 6x + 20 \\ {3x}^{2} + 16x + 20 - 36x - 72 = 0 \\ {3x}^{2} - 20x - 52 = 0 \\ (3x - 26)(3x + 6) \\ (3x - 26)(x + 2) \\ x = \frac{26}{3} ataux = - 2 \\ \\ b. \\ |2x + 5| - 3 > 7 \\ |2x + 5| > 10 \\ 2x + 5 < - 10 \\ x_{1} < - \frac{15}{2} \\ 2x + 5 > 10 \\ x_{2} > \frac{5}{2} [/tex]