bantu jwb kakak-kakak yg ilmu nya byk yaaa

4x + y >= 4..(1)
2x + 3y >=6..(2)
x >= 0
x >= 0
4x + y = 4. (2)×2
4x + 6y = 12
------------------ -
-5y = -8
y = 8/5 = 1,6
dari (2) 2x + 3y = 6
2x + 3.(1,6) = 6
2x + 4,8 = 6
2x = 6 - 4,8
2x = 1,2
x = 1,2 / 2
x = 0,6
Didapat 3 titik ( 3,0),(0,4),(0,6 , 1,6)
f (x, y ) = 5x + 5y
f (3,0) = 5.3 + 5.0 = 15
f (0,4) = 5.0 + 5.4 = 20
f (0,6 , 1,6) = 5(0,6) + 5(1,2)
= 3 + 6
= 9
Jadi nilai minimum= 9