2log7+2log16-2log28=...

Logaritma
Kelas X

²log 7 + ²log 16 - ²log 28
= ²log ⁷/₂₈ + ²log 16
= ²log ¼ + 4
= ²log 2⁻² + 4
= -2 + 4
= 2

Ingat :
1.) ᵃlog a - ᵃlog b = ᵃlog (a / b)
2.) ᵃlog aᵇ = b

[tex] {}^{2} log(7) + {}^{2} log(16) - {}^{2} log(28) \\ = {}^{2} log( \frac{7 \times 16}{28} ) \\ = {}^{2} log( \frac{16}{4} ) \\ = {}^{2} log_{}(4) \\ = {}^{2} log_{}(2 {}^{2} ) \\ = 2. {}^{2} log(2) \\ = 2 \times 1 \\ = 2[/tex]