3^Log akar6 -------------------- (3^Log 18)2^ - ( 3^Log 2)2^ pliss bantuu kakk bangg , pake cara yaa di foto kalau bisaaa, makasihhh ket : 3^ = pangkat 3 2^ = p

[tex] \frac{ {}^{3} log( \sqrt{6} ) }{( {}^{3} log18) {}^{2} - ( {}^{3} log2) {}^{2} } \\ = \frac{ {}^{3} log(6 {}^{ \frac{1}{2} } ) }{( {}^{3} log18 + {}^{3} log2) ( {}^{3} log18 - {}^{3} log2 ) } \\ = \frac{ \frac{1}{2}. {}^{3} log(6) }{(2. {}^{3} log6)( {}^{3} log9) } \\ = \frac{1}{8} [/tex]

Jawaban = A