Cos (a+b) + cos (a-b) : sin (a+b) - sin (a-b) = cot b
Matematika
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Pertanyaan
Cos (a+b) + cos (a-b) : sin (a+b) - sin (a-b) = cot b
1 Jawaban
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1. Jawaban Anonyme
TriGonoMetRi
[cos (a + b) + cos (a - b)] / [sin (a + b) - sin (a - b)]
= [2 cos (a+b + a-b)/2 cos (a+b - (a-b))/2] / [2 cos (a+b + a-b)/2 sin (a+b - (a-b))/2]
= [2 cos a cos b] / [2 cos a sin b]
= cos b / sin b
= cot b
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