bantu dong kak besok di kumpulin :)

AP = 3 cm
PD = 5 cm
BC = 10 cm

AD = AP + PD
       = (3 + 5) cm
       = 8 cm

Perbandingan ukuran :

[tex] \frac{AP}{AD} = \frac{BQ}{BC} \\ \\ \frac{3}{8} = \frac{BQ}{10} \\ \\ 8BQ = (3).(10) \\ \\ 8BQ = 30 \\ \\ BQ = \frac{30}{8} \\ \\ BQ=3 \frac{6}{8}=3 \frac{3}{4}=3 + \frac{3}{4} = 3 + 0,75 = 3,75 [/tex]

Jawaban (A)