Tolong kak bantu saya mengerjakan

[tex]elimisiy \\ \frac{1}{x} + \frac{1}{y} = \frac{1}{6} | \times \frac{1}{2} | \\ \frac{1}{2x} - \frac{1}{2y} = - \frac{5}{12} | \times 1| \\ ( \frac{1}{2x} + \frac{1}{2y} = \frac{1}{12} ) + ( \frac{1}{2x} - \frac{1}{2y} = - \frac{5}{12} ) \\ \frac{2}{2x} = - \frac{4}{12} \\ 2x = - \frac{12}{4} \times 2 \\ 2x = - 6 \\ x = - 3 \\ \\ subs \: x = - 3 \\ \frac{1}{x} + \frac{1}{y} = \frac{1}{6} \\ \frac{1}{ - 3} + \frac{1}{y} = \frac{1}{6} \\ \frac{1}{y} = \frac{1}{6} + \frac{1}{3} \\ \frac{1}{y} = \frac{1}{2} \\ y = 2[/tex]
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