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Determinana C= -6

dengan Sarrus

[tex] det \left|\begin{array}{ccc}1&2&-1\\2&1&1\\4&0&2\end{array}\right \left\begin{array}{ccc}1&2\\2&1\\4&0\end{array}\right] \,= [/tex]


[tex]p = 1(-1)(2) + 2(1)(4) -1(2)(0) = -2 + 8 +0 = 6\\q = (4(-1)(-1) +0(1)(1) +2(2)(2)=4+0+8 = 12\\ det = p - q = 6 - 12 = -6[/tex]