(4√3+2√5)(4√3-2√5) besera caranya

[tex] = (4 \sqrt{3} + 2 \sqrt{5} )(4 \sqrt{3} - 2 \sqrt{5}) \\ = 16 \sqrt{9} - 8 \sqrt{15} + 8 \sqrt{15} - 4 \sqrt{25} \\ = 16 \sqrt{9} - 4 \sqrt{25} \\ = (16 \times 3) - (4 \times 5) \\ = 48 - 20 \\ = 28[/tex]

(4√3+2√5)(4√3-2√5)
= 16 x 3 - 4 x 5
= 48 - 20
= 28