f(x)=x2-x+2.jika diketahui Domain D=[0,1,2]maka RANGE fungsi tsb adalah...... A(2,0,4) B.(0,4) C.(2,4) D.(2) TOLONG DIJAWAB

f(x) = x^2 -x +2
f (0) = 0^2 -0 +2 = 2
f (1) = 1^2 - 1 +2 = 2
f (2) = 2^2 -2 +2 = 4
Range = { 2, 4 }

f(x) = x² - x + 2
Domain = {0, 1, 2}

f(0) = (0)² - (0) + 2 = 0 - 0 + 2 = 2
f(1) = (1)² - (1) + 2 = 1 - 1 + 2 = 2
f(2) = (2)² - (2) + 2 = 4 - 2 + 2 = 4

Range fungsi adalah {2, 4}........Jawaban (C)