Matematika

Pertanyaan

Mohon bantuannya. Menggunakan cara
Mohon bantuannya. Menggunakan cara

2 Jawaban

  • Matriks
    Kelas X

    [tex] \left(\begin{array}{cc}2 & 1 \\ 1 & -3 \end{array}\right) \left(\begin{array}{cc}2 -x \\ 3x + 2y \end{array}\right) = \left(\begin{array}{cc} 13 \\ -4 \end{array}\right) \\
    \left(\begin{array}{cc} 4 - 2x + 3x + 2y \\ 2 - x - 9x - 6y \end{array}\right) = \left(\begin{array}{cc} 13 \\ -4 \end{array}\right) \\
    \left(\begin{array}{cc} x + 2y + 4 \\ -10x - 6y + 2 \end{array}\right) = \left(\begin{array}{cc} 13 \\ -4 \end{array}\right) [/tex]

    x + 2y + 4 = 13
    x + 2y = 9 |x 3|
    3x + 6y = 27 ... (i)

    -10x - 6y + 2 = -4
    10x + 6y = 6 ... (ii)

    Eliminasi (i) dan (ii)

    3x + 6y = 27
    10x + 6y = 6
    ––––––––– (–)
    -7x = 21
    x = -3

    3(-3) + 6y = 27
    6y = 27 + 9
    6y = 36
    y = 6

    5y - 2x = 5(6) - 2(-3)
    = 30 + 6 = 36
  • 5y - 2x = 5(6) - 2(-3) = 36