a) 2(-e+12) = 6(e - 10) b) 2(g - 1) - 6g = 10 - 2(g - 4) c) 2( -2 + j) = 10
Matematika
EverillMaharani
Pertanyaan
a) 2(-e+12) = 6(e - 10)
b) 2(g - 1) - 6g = 10 - 2(g - 4)
c) 2( -2 + j) = 10
b) 2(g - 1) - 6g = 10 - 2(g - 4)
c) 2( -2 + j) = 10
2 Jawaban
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1. Jawaban Haryesa
a. 2(-e+12)=6(e-10)
-2e+24=6e-60
-8e=-84
e=10,5
b.2(g-1)-6g=10-2(g-4)
2g-2-6g=10-2g+8
-2g=20
g=-10
c.2(-2+j)=10
-4+2j=10
2j=14
j=7 -
2. Jawaban beifu
a. -2e+24 = 6e-60
-2e-6e = -60-24
-8e = -84
-e = -84 / -8
-e = -8.5