nilai koordinat titik puncak dari fungsi kuadrat f(x)=3x^2+5x-2

jawab

f(x)= 3x²+ 5x -2

f'(x) = 0
6x + 5 = 0
x = - 5/6

f(-5/6) = 3 (-5/6)² + 5 (-5/6) - 2
f(-5/6) = -49/12

titik puncak ( x, f(x))
= (- 5/6  , -49/12)