pliss jawab no 6 dan 7

6.
[tex] \frac{2-3x}{6x+5} + \frac{x+1}{2x-1} \\ = \frac{(2-3x)(2x-1)+(x+1)(6x+5)}{(6x+5)(2x-1)} \\ = \frac{(4x-2-6x^{2}+3x)+(6x^{2}+5x+6x+5)}{(6x+5)(2x-1)} \\ = \frac{(-6x^{2}+7x-2)+(6x^{2}+11x+5)}{(6x+5)(2x-1)} \\ = \frac{(-6x^{2}+6 x^{2})+(7x+11x)+(-2+5)}{(6x+5)(2x-1)} \\ = \frac{18x+3}{(6x+5)(2x-1)} [/tex]

answer = D

7.
p = panjang
l = lebar
L = luas

p = l + 8 >> p = x + 8
l = x

Luas kertas = panjang kertas × lebar kertas
= ((x + 8) + (0,5×2)) × (x + (0,5×2))
= (x + 9) × (x + 1)
[tex]= x^{2} +x+9x+9 \\ = x^{2} +10x+9[/tex]

jawaban = B