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1. Q=540
t=3 menit=180 detik
I?
I=Q/t
540/180=3A

2. L=50m
A=2mm^2= 2x10^-6 m^2
Rho=6x10^-8
R?
R=rho x L : A
=6x10^-8 x 50 : 2x10^-6
=150x10^-2
=1.5 ohm

--Listrik Dinamis--

no. 1

Diketahui:
Q = 540 C
t = 3 menit = 180 detik

Ditanya: Kuat arus listrik ( I )?

Jawab:
I = Q/t
I = 540/180
I = 3 Ampere

no. 2

Diketahui:
ρ = 6 x 10^-8 Ωm
L = 50 m
A = 2 mm² = 2 x 10^-6 m²

Ditanya: Hambatan kawat ( R )?

Jawab:
R = ( ρ x L ) / A
R = ( 6 x 10^-8 x 50) / 2 x 10^-6
R = ( 300 x 10^-8 ) / 2 x 10^-6
R = 150 x 10^-2
R = 1,5 Ω