tolong dijawab pake cara

jawab

AB=BC= 10
AC = 1/3 AG = 16
t = tinggi ΔABC
t = √(AB² - (1/2 AC)²
t = √(10² -8²)
t  = 6

Luas  ΔABC = 1/2 (AC)(t) = 1/2 (16)(6)= 48


tinggi trap = 2t = 12
KJ = 34
AG = 48
Luas Trap = 1/2  (KJ+AG)(t)
L trap = 1/2 (32+48)(12)= 480


luas diarsir  = Luas trap - 3 xluas Δ
L = 480- 3(48)
L = 336