tentukan persamaan garis yang melalui titik p(1,-3) dan Q(3,-2)

Jawab :

m : y2 - y1/ x2 - x1 = (-2) - (-3)/ 3 - 1 = 1/2

y - y1 = m(x - x1)
y - (-3) = 1/2(x - 1)
y + 3 = 1/2(x - 1)
y + 3 = 1/2x - 1/2 x 1
y + 3 = 1/2x - 1/2
_________________ x 2
2 . y + 3 . 2 = 1/2x . 2 - 1/2 . 2

2y + 6 = 1x - 1
2y + 6 - x + 1 = 0
2y - x + 7 = 0

m = y2 - y1 / x2 - x1
= -2 - -3 / 3 - 1
= -2 + 3 / 2
= ½
y - y1 = m (x - x1)
y - -3 = ½ (x - 1)
y + 3 = ½x - ½
2y + 6 = x - 1
2y = x - 1 - 6
2y = x - 7
-x + 2y - 7 = 0