Tentukan persamaan garis yang melalui titik (5,0) dan (0,-3)

Jawab :

m = y2 - y1/ x2 - x1 = (-3) - 0/ 0 - 5 = -3/-5 = 3/5

y - y1 = m(x - x1)
y - 0 = 3/5(x - 5)
y - 0 = 3/5x - 3/5 . 5
y - 0 = 3/5x - 15/5
_________________ x 5
5 . y - 0 . 5 = 3/5x . 5 - 15/5 . 5

5y - 0 = 3x - 15
5y - 0 - 3x + 15 = 0
5y - 3x + 15 = 0
-3x + 5y + 15 = 0