Diketahui y = x sec x² Ditanya dy/dx
Matematika
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Pertanyaan
Diketahui y = x sec x² Ditanya dy/dx
1 Jawaban
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1. Jawaban Anonyme
jawab
y = x . sec x²
u = x²
du/dx = 2x
t = sec u
dt/du = sec u. tan u
dt/dx = dt/du. du/dx
dt/dx = sec x². tan x². 2x
y = x. sec x²
y = u . t
y' = u' t + u t'
y' = sec x² + x . sec x². tan x². 2x
y' = sec x² + 2x² . sec x². tan x²