Hasil dari Sin 7x cos 5x dx?

InTegraL

sin 7x cos 5x = 1/2 (sin (7x + 5x) + sin (7x - 5x)) = 1/2 (sin 12 x + sin 2x)

∫sin 7x cos 5x dx
= 1/2 ∫(sin 12x + sin 2x) dx
= 1/2 (-1/12 ∫dcos 12x - 1/2 ∫dcos 2x)
= -1/24 cos 12x - 1/4 cos 2x + C