Matematika

Pertanyaan

Tolong bantu no 4 pakek cara ya
Tolong bantu no 4 pakek cara ya

1 Jawaban

  • [tex] \sqrt{192} - \sqrt{75} + ( \frac{1}{3} \sqrt{3} ) {}^{ - 1} \\ = \sqrt{8 {}^{2} \times 3} - \sqrt{5 {}^{2} \times 3} \: + ( \frac{1}{3} \sqrt{3} ) {}^{ - 1} \\ = 8 \sqrt{3} - 5 \sqrt{3} + (\frac{ \sqrt{3} }{3} ) {}^{ - 1} \\ = 8 \sqrt{3} - 5 \sqrt{3} + \frac{3}{ \sqrt{3} } \\ = 8 \sqrt{3} - 5 \sqrt{3} + \frac{3}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ = 8 \sqrt{3} - 5 \sqrt{3} + \frac{3 \sqrt{3} }{3} \\ = 8 \sqrt{3} - 5 \sqrt{3} + \sqrt{3 } \\ = 4 \sqrt{3} [/tex]

    Jadi, jawabannya D.