sama penjelasannya juga yaa

[tex] \frac{x - 3}{x + 2} \leqslant \frac{x + 4}{x - 1} \\ (x - 3)(x - 1) = (x + 4)(x + 2) \\ { x}^{2} - x - 3x + 3 = {x}^{2} + 2x + 4x + 8 \\ {x}^{2} - 4x + 3 = {x}^{2} + 6x + 8 \\ [/tex]