mohon dijawab yaaa :)
Matematika
Yurafara13
Pertanyaan
mohon dijawab yaaa :)
1 Jawaban
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1. Jawaban MichaelChen
m f(x) = [tex] \frac{x-3}{2x+1} [/tex]
y = [tex] \frac{x-3}{2x+1} [/tex]
2xy + y = x - 3
2xy - x = - 3 - y
x (2y - 1) = - 3 - y
x = [tex] \frac{-3-y}{2y-1} [/tex]
[tex] f^{-1} [/tex] (x) = [tex] \frac{-x-3}{2x-1} [/tex]
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