Jika Ar Na = 23,0 = 16, H=1, dan C= 12 maka Mr NaHCO3 adalah

Mr NaHCO3
= (1 x ar Na) + (1 x ar H) + (1 x ar C) + (3 x ar O)
= (1 x 23) + (1 x1) + (1 x 12) + (3 x 16)
= 23 + 1 + 12 + 48
= 84 gr/mol

1 x Ar Na + 1 x Ar H + 1 x Ar C + 3 x Ar O
= 1 x 23 + 1 x 1 + 1 x 12 + 3 x 16
= 23 + 1 + 12 + 48
= 84