himpunan penyelesaian |x-3|<|x-2| adalah

|x-3| < |x-2|
|x-3|-|x-2| < 0
(X-3)^2 - (x-2)^2 < 0
((x-3)+(x-2))((x-3)-(x-2)) < 0
(2x-5)(-1) < 0

x1 = 5/2

HP : x < 5/2

Maaf jika ada kesalahan :)

Kelas 10 Matematika
Bab Nilai Mutlak

|x - 3| < |x - 2|
(x - 3)² < (x - 2)²
(x - 3)² - (x - 2)² < 0
(x - 3 + x - 2) (x - 3 - x + 2) < 0
(2x - 5) . (-1) < 0
2x - 5 > 0
2x > 5
x > 5/2

HP = { x | x > 5/2, x € bilangan real }