integral 10x(8x2-1)4 dx

InTegraL

∫x^n = 1/(n+1) . x^(n+1) + C

Misal :
u = 8x² - 1
du/dx = 16x
du = 16x dx
10 du = 16 . 10x dx
10x dx = 10/16 du
10x dx = 5/8 du

•••
∫10x (8x² - 1)^4 dx
= 5/8 ∫u^4 du
= 5/8 . u^5 /5 + C
= 1/8 u^5 + C
= 1/8 (8x² - 1)^5 + C