tentukan turunan pertama dari y= e akar x³

y= e (akar x³)    atau     y= (e^x)(akar x³)???
y= e (akar x³) = x^(3/2)
y' = (3/2)x^(1/2)

y= (e^x)(akar x³)
y' = (e^x)(akar x³) + (e^x)((3/2)x^(1/2))= (e^x)x^(1/2)*(x + (3/2))