Titik puncak fungsi kuadrat f(x)=3x+5x+4 adalah

f (x) = 3x^2 +5x +4.
sumbu simetri x = -5/2.3 = -5/6
sumbu simetri dllalui garafik, maka
f (-5/6) = 3(-5/6)^2 + 5(-5/6) + 4
= 3(25/36) - 25/6 + 4
= 75/36 -150/36 + 144/36
= 69/36
= 23/12
= 1 11/12
Puncak ( -5/6, 1 11/12 )

Fungsi Kuadrat

Mencari titik puncak menggunakan turunan
f(x) = 3x² + 5x + 4

syarat minimum (titik puncak/balik minimum) :
f'(x) = 0

f'(x) = 0
6x + 5 = 0
x = -5/6

y = f(-5/6) = 3(-5/6)² + 5(-5/6) + 4
y = 25/12 - 50/12 + 48/12
y = 23/12

Titik puncak = (x,y) = (-5/6 , 23/12)