integral dari df(x)/dx = 18(3x+2)^5 serta caranya ya

jawab

u = 3x + 2
du = 3 dx
18 dx = 6 du

∫ 18(3x +2)⁵ dx =  ∫ 6 u⁵ du = u⁶ + c
= (3x+2)⁶ + c
= 

integral 18( 3x + 5)^5 dx = ....
misal u = 3x + 5
du/dx = 3
3 dx = du
dx = du/3, maka
integral 18 u^5 du/3
= 18/3 integral u^5 du
= 6 u^(5+1) /(5+1) + c
= 6u^6 / 6
= u^6 + c
= (3x + 2)^6 + c