Turunan fungsi dari: A. F(x)=akar 3 dari x², maka f'(4)= B. F(x)=(2x²-5)(4x+2), maka f'(3)= C.g(t)=3t+3/5t+2, maka g'(2)=

jawab

a) 
f(x) =  ∛x²  = x^(2/3)
f '(x) = 2/3 x^(1/3) 
f '(4) = 2/3 ∛4

b.
f(x)= (2x²- 5)(4x + 2)
f'(x) = 4x(4x +2) + 4(2x² -5)
f'(x ) = 16x² + 8x + 8x² - 20
f'(x) = 24x² + 8x - 20
f' (3)= 24(9) + 8(3) - 20 = 220

c.
g(t) =  (3t + 3)/ (5t + 2) 
f'(t) =  { 3(2)+ 5(3) } /( 5t + 2)²
f ' (t) = 21/(5t +2)²
f ' (2) = 21/ (12)²= 7/48