suku banyak f(x) = bx^3 - x^2 + 12x - 8 dibagi oleh (3x-1) memberikan sisa -4. nilai b yang memenuhi adalah..

f(x) = bx^3 - x^2 + 12x - 8

3x - 1 = 0
x = 1/3

f(1/3) = -4
b(1/3)³ - (1/3)² + 12(1/3) - 8 = -4
b/27 - 1/9 + 4 - 8 = -4
b/27 = -4 + 4 + 1/9
b/27 = 1/9
b = 27/9
b = 3