Integral dx / x²- 2x - 8 gimana ya pak pembahasannya ?

jawab

∫ dx/ (x² - 2x - 8)  = ∫ dx/ (x - 4)(x  + 2) = ∫ a/(x-4) - b/(x- 2) dx
= ∫ 1/ 6(x-4) - 1/ 6(x+ 2) dx 
= 1/6 ∫ 1/(x+4) dx - 1/(x+2) dx
= 1/6 Ln(x+4) - 1/6 ln(x +2)  + c