Matematika

Pertanyaan

Lim x => 1 1 - cos²(x-1)/4x²-8x+4

1 Jawaban

  • jawab

    limit(x -->1) (1 - cos²(x-1)) / (4x² - 8x + 4)

    limit(x--> 1) (sin² ( x- 1) /  4 (x -1)² )

    x= 1
    limit = (x-1)²/ 4 (x -1)²
    limit = 1/4

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