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Matematika
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2 Jawaban
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1. Jawaban BarraIlhamM
AB = AP + DC + QB.
60 = x + 30 + x.
60 = 2x + 30.
60 - 30 = 2x.
30 = 2x.
30/2 = x.
15 = x.
AD² = AP² + DP².
DP² = AD² - AP².
DP = √AD² - AP².
DP = √30² - 15².
DP = √900 - 225.
DP = √675.
DP = √225 × √3.
DP = 15√3cm.
L = ½ × (s1 + s2) × t.
L = ½ × (30 + 60) × 15√3.
L = ½ × 90 × 15√3.
L = ½ × 1.350√3.
L = 675√3cm². -
2. Jawaban Faizal0502
DC = PQ = 30 cm
AP = BQ = (AB - PQ) /2 = (60 - 30) /2 = 30/2 = 15 cm
DP² = √AD² - AP²
= √30² - 15²
= √900 - 225
= √675
= √225 × √3
= 15√3 cm
luas trapesium
=½(a+b) × t
=½(60 + 30) × 15√3
=½(90) × 15√3
=45 × 15√3 cm²
=675√3 cm²
semoga membantu