Mohon bantuannya kak, buat nilai tugas supaya rapot tuntas

y = 1/6x^2.
Titik potong kurva dengan y =4
4 = 1/6x^2
x^2 = 4/6
x = +/-√(4/6)
x = +/- √(2/3)
x = +/- (2/3)√3
Luas = integral (1/6)x^2 ) dx
= 2x^3 dengan batas (-2/3)√3 sampai (2/3)√3
= {(2/3)√3}^3 - {(-2/3)√3}^3
= {(8/27)3√3 } - {-8/27)3√3}
= {(8/9)√3} - {(-8/9)√3 }
= {(8/9)√3} + {(8/9)√3)
= (16/9)√3