tolong jawab yg bisa ya terimakasih

[tex]f(x) = 6 \sin(4x - 60 ^{o} ) + 2 \\ \\ f( \frac{\pi}{6} ) = ... \\ \\ \pi = 180 {}^{o} \\ \frac{\pi}{6} = 30 {}^{o} \\ \\ f(30 {}^{o} ) = 6 \sin(4(30) - 60) + 2 \\ \\ = 6 \sin(120 - 60) + 2 \\ \\ = 6 \sin(60) + 2 \\ \\ = 6( \frac{1}{2} \sqrt{3} ) + 2 \\ \\ = 3 \sqrt{3} + 2[/tex]
Jawaban : D