Tolong dijawab ya no.5 dan 6

5.]
x = perempuan , y = laki²
[tex] \frac{x}{y} = \frac34 \\
x = \frac34y \ ... (i) \\
\\
\frac{x + 3}{y-2} = \frac{9}{10} \\
10x + 30 = 9y - 18 \\
Masukkan \ persamaan \ (i) \\
10(\frac34y) + 30 = 9y - 18 \\
\frac{30}{4}y - 9y = -48 \\
y = 32 \\
\\
x = \frac34 (32) \\
x = 24 [/tex]

Jumlah seluruh = 24 + 32 = 56 orang [A]

6.]
S = 89 orang
diatas 30 = 72 orang
dibawah 65 = 65 orang

Diantara 30 - 65 = (72 + 65) - 89
= 48 orang [C]