Tolong bantu jawab! seperangkat karyu bridge tanpa joker diambil empat kartu secara acak. berapakah peluang kejadian2 berikut? a.kejadian terambilnya 4 karu ber

S adalah pengambilan 4 kartu dari 52
n(S) = 52 C 4
= 52! / (52-4)!.4!
= 52 × 51 × 50 × 49 × 48! / 48!.4!
= 52 × 51 × 50 × 49 / 4 × 3 × 2 × 1
= 13 × 17 × 25 × 49
= 270.272
a) 4 kartu no.8
n(A) = 4 C 4 = 1
P(A) = n(A)/n(S)
= 1/270.272
b) 2 king dan 2 queen
= 4 C 2 × 4 C 2
= 6 × 6 = 36
P(B) = 36/270.272
c) 4 merah dari 26
= 26 C 4
= 26!/(26-4)!.4!
= 26×25×24×23×22!/22!.4!
= 26×25×24×23/4×3×2×1
= 26×25×23
= 14.640
P(C) = 14.640/270.725
= 2.928/54.125.