jika reaksi antara 6,0 gram etana C2H6(Mr=30)dengan 7,1gram Cl2(Mr=17)menghasilkan 5,16gram C2H6Cl(Mr=64,5)maka persentase rendaman etil klorida adalah

Dik :
massa etana = 6 gr
Mr C2H6 = 30
m Cl2 = 7,1 gr
Mr Cl2 = 71
m C2H6Cl = 5,16 gr
Mr C2H6Cl = 64,5

Dit :
%rendaman C2H6Cl....?

Dijawab :
Mol C2H6:
Mol = m etana / Mr C2H6
Mol = 6 gr / 30
Mol = 0,2 mol

Mol Cl2 :
Mol = m Cl2 / Mr Cl2
Mol = 7,1 gr / 71
Mol = 0,1 mol

Mol C2H5Cl :
Mol = m C2H5Cl / Mr C2H5Cl
Mol = 5,16 gr / 64,5
Mol = 0,08 mol

Reaksi :
.... C2H6 + Cl2 => C2H5Cl + HCl
M = 0,2 ----- 0,1
R = - 0,1 ---- - 0,1 --------------- + 0,1
S = 0,1 ------------------ 0,1

Mol dlm teori C2H6Cl = 0,1 mol

%rendaman = (mol nyata / mol teori) × 100%
= (0,08 mol / 0,1 mol) × 100%
= 80%