Tolong bantu jawab! tentukan pusat, puncak, fokus, dan asimtot hiperbola (×-3)^2 ÷ 25 + (y+1)^2 = 1

jawab

(x - 3)² /25  + (y +1)² = 1 --> (x - p)/a² + (y- q)²/b² = 1
p = 3
q = -1
a² = 25 --> a= 5
b² = 1
c² = a² + b² = 26
c = √26

Pusat (p,q) = (3,-1
Puncak A12 = (p +_a, q)
A1  = {(2 +5), -1 }
A1 = (7,-1)

A2 = {(2 -5), -1}
A2 = (-3, - 1)

Fokus F12 = (p+_ c, q)
F1=  {(3 + √26),  - 1}
F2 = {(3 - √26), - 1}

Asimptot y - q = +_b/a (x -p)
y +1 = +_ 1/5 (x - 3)

y+ 1 = 1/5 (x -3)
5(y +1)= x - 3
5y + 5 = x - 3
5y = x - 8
x - 5y = 8

y+1 = - 1/5 ( x - 3)
5(y +1) = -x + 3
5y + 5 = -x + 3
5y = - x - 2
x + 5y = - 2