nilai [tex] cos^{2} [/tex]A + [tex] tan^{2} [/tex]A - [tex] sec^{2} [/tex]A =
Matematika
Angga092
Pertanyaan
nilai [tex] cos^{2} [/tex]A + [tex] tan^{2} [/tex]A - [tex] sec^{2} [/tex]A =
1 Jawaban
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1. Jawaban kekkaiisshi
cos² a + tan² a - sec² a = cos² a + tan² a - (tan² a - 1) = cos² a - 1