Tolong bantu jawab! carilah rumus untuk fungsi g(x), jika diketahui: a) f(x)= x-2 dan (fog) (x)= 3x+1 b) f(x)= 4x-1 dan (fog) (x)= x pangkat 2+x+1 c) f(x)= 4x-1

a) f(x) = x - 2. (fog) (x) = 3x + 1
f { g(x) } = 3x + 1
g(x) -2 = 3x +1
g(x) = 3x + 1 + 2
g(x) = 3x + 3
b) f(x) = 4x - 1 . (fog) (x) = x^2 + x + 1
f { g(x) } = x^2 + x + 1
4.g(x) - 1 = x^2 + x + 1
4.g(x) = x^2 + x +2
g(x) = (x^2 + x + 2)4
c) f (x) = 4x - 1, (fog)(x) = 2x^2-x +3
f { g(x) } = 2x^2 -x +3
4.g(x) - 1 = 2x^2 - x + 3
4.g(x) = 2x^2 - x + 4
g(x) = (2x^2 - x + 4)/4
d) f(x) = x^2 - x + 4 dan (fog)(x) = 3 -2x
f { g(x) } = 3 -2x
{g(x)}^2 - g(x) + 4 = 3 -2x
{g(x) }^2 - g(x) = -2x -1
{ g(x) - 1/2 }^2 - 1/4 = -2x -1
{ g(x) - 1/2 }^2 = -2x - 1 +1/4
{ g(x) - 1/2 }^2 = -2x -3/4
g(x) - 1/2 = +/- √(-2x - 3/4)
g(x) = +/- √(-2x -3/4) + 1/2
syarat -2x - 3/4 >= 0
-2x >= 3/4 ( kalikan -1/2)
x <= -3/8