Matematika

Pertanyaan

hitunglah permutasian pencacahan dari
a. P (20,17)
b. P (15,13)

2 Jawaban

  • a) P (20,17) = 20! /(20-17)!
    = 20! / 13!
    = 20 × 19 × 18 × 17 × 16 × 15 × 14 × 13!/13!
    b) P ( 15 , 13) = 15! / (15-13)!
    = 15! / 2!
    = 15 × 14 × 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3
    = .....
  • Kelas 10 Matematika
    Bab Peluang

    ^ = pangkat

    1] 20P17
    = 20 ! / (20 - 17) !
    = 20 . 19 . 18 . 17 . 16 . 15 . 14 . 13 . 12 . 11 . 10 . 9 . 8 . 7 . 6 . 5 . 4 . 3 ! / 3 !
    = 20 . 19 . 18 . 17 . 16 . 15 . 14 . 13 . 12 . 11 . 10 . 9 . 8 . 7 . 6 . 5 . 4
    = 4,05483668 x 10^17

    2] 15P13
    = 15 ! / (15 - 13) !
    = 15 . 14 . 13 . 12 . 11 . 10 . 9 . 8 . 7 . 6 . 5 . 4 . 3 . 2 ! / 2 !
    = 15 . 14 . 13 . 12 . 11 . 10 . 9 . 8 . 7 . 6 . 5 . 4 . 3
    = 653.837.184.000

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