(3logx)^2-3logx^3+2=0

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

(^3log x)² - ^3log x^3 + 2 = 0
(^3log x)² - 3 . ^3log x + 2 = 0

^3log x = p

p² - 3p + 2 = 0
(p - 2) (p - 1) = 0
p - 2 = 0
p = 2

^3log x = p
^3log x = 2
x = 3²
x = 9

p - 1 = 0
p = 1

^3log x = p
^3log x = 1
x = 3^1
x = 3

Maka, x = 3 atau x = 9

Mata Pelajaran : Matematika Peminatan
Kelas : 10
Bab : 02 - Fungsi Logaritma



[tex]( {}^{3} logx) {}^{2} - {}^{3} log(x {}^{3 + 2} ) = 0 \\ {}^{3} log(x {}^{2} ) - {}^{3} log(x {}^{5} ) = 0 \\ {}^{3} log(x {}^{2} ) - 5. {}^{3} log(x) = 0 \\ ( {}^{3} logx) ( {}^{3} logx - 5) = 0 \\ \\ maka \\ {}^{3} log(x) = 0 \\ x = 1 \\ dan \\ {}^{3} log(x) - 5 = 0 \\ x = 243 [/tex]
HP : { 1 , 243 }