Tolong dibantu kk soalnya

No.6
f(x) = √(3x) . g(x) 
f '(x) = √(3x) . g '(x) + 3/(2√(3x)) . g(x)
jadi
f '(3) = √(3(3)) . g '(3) + 3/(2√(3(3))) . g(3)
= 3 . 2 + 3/(2 . 3) . 4
= 6 + 2
= 8

No.7
f(2/√(2x-1)) = x

2/√(2x-1) = 1
√(2x-1) = 2
2x - 1 = 4
2x = 5
x = 5/2

jadi f(1) = 5/2