Jika f(x) =x+2/2x+3 dan g(x) = 3x-1 maka(gof) (-2)=

gof(x)=g(f(x))
g(f(x))=g(x+2/2x+3)
=3(x+2/2x+3)-1
=3x+6/2x+3-1

gof(-2)=3(-2)+6/2(-2)+3-1
=(-6+6/-4+3)-1
=(0/-1)-1
=0-1
=-1

(gof) (-2) =
g(f(x)) = g (-2 +2/ 2(-2) +3)
g (0/-1)
g (0)
3(0) - 1 = - 1
(gof) (-2) = - 1