tlong di jawab pake cara

Jawabannya:

7log2= a
2log3= b

6log14 ...
=2log14/2log6
= 2log7+2log2/2log2+2log3
= 1/7log2+1/1+b
= 1/a+1/1+b
= 1+a/a/1+b
= 1+a/a(1+b)
= 1+a/a+ab

Jadikan Jawaban Terbaik Ya

7log 2 = a dan 2log 3 = b
6log 14 = log 14 / log 6
= log 2×7 / log 2×3
= ( log 2 + log 7 ) / (log 2 + log 3).
ganti dengan bilangan pokok 2, maka
= (2log 2 + 2log 7)/(2log 2 + 2log 3)
= ( 1 + 1/a) / ( 1 + b )
= { (a+1)/a } / (1+b)
= (a + 1) / a(b + 1)....C