nilai maksimum z=3x + 2y dari sistem pertidaksamaan 2x+y >3,×+y <6,×>1,y>0

jawab

2x + y = 3
x = 0, y = 3
y = 0, x = 3/2

x +y = 6
x = 0 , y = 6
y = 0 , x = 6

x = 1

titik sudut HP 
A (1,1) --> z = 3(1) +2(1) = 5
B (3,2) --> Z= 3(3) + 2(2) = 13
C (1,5) --> Z= 3(1) + 2(5) = 13
D (0,6) --> z = 3(0) + 2(6) = 12
Nilai maksimum Z = 13